Interactive practice questions
Find the measure in degrees of the acute angle satisfying $\sin\theta=\frac{1}{\sqrt{2}}$sinθ=1√2.
Easy
1min
Find the measure of the angle satisfying $\cos\theta=\frac{1}{\sqrt{2}}$cosθ=1√2 for $0^\circ<\theta<90^\circ$0°<θ<90°.
Easy
< 1min
Find the measure in degrees of the acute angle satisfying $\tan\theta=\sqrt{3}$tanθ=√3.
Easy
< 1min
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