An expression in the form $a^n$an is called an exponential expression. The letter $a$a is called the base and $n$n is called the exponent or index. Both the base and index can be a positive or negative integer or fraction.
The product rule applies when we have the product of multiple exponential expressions with the same base and states:
$a^m\times a^n$am×an | $=$= | $a^{m+n}$am+n |
The quotient rule applies when we have multiple exponential expressions with the same base divided by each other and states:
$a^m\div a^n$am÷an | $=$= | $a^{m-n}$am−n |
The zero index rule applies when any number or expression is raised to the power of $0$0 and states:
$a^0$a0 | $=$= | $1$1 |
The quotient rule applies when we have multiple exponential expressions with the same base divided by each other and states:
$\left(a^m\right)^n$(am)n | $=$= | $a^{mn}$amn |
The negative index rule applies when we have an exponential expressions with a negative index and states:
$a^{-m}$a−m | $=$= | $\frac{1}{a^m}$1am |
The fractional index rule applies when we have an exponential expression with with a fractional index and states:
$a^{\frac{m}{n}}$amn | $=$= | $\sqrt[n]{a^m}$n√am |
The fractional base rule applies when we have a fractional base number raised to a power and states:
$\left(\frac{a}{b}\right)^m$(ab)m | $=$= | $\frac{a^m}{b^m}$ambm |
Be careful when using index rules with numerical bases. Index laws still apply and the bases have to be the same! For example, if we have an expression such as $3^x\times9^x$3x×9x we can not apply any of these rules as $3\ne9$3≠9. However, if we can convert $9$9 into the same base of $3$3 we can proceed as follows:
$3^x\times9^x$3x×9x | $=$= | $3^x\times\left(3^2\right)^x$3x×(32)x |
$=$= | $3^x\times3^{2x}$3x×32x | |
$=$= | $3^{x+2x}$3x+2x | |
$=$= | $3^{3x}$33x |
Let's have a look at how to simplify (to simplest index form) some more complicated examples.
Simplify the expression $\frac{6^{p-4q}\times36^{2q+p}}{6^{5p-3q}}$6p−4q×362q+p65p−3q
Think: First make sure all terms have the same base and be careful with the order of operations when subtraction of groups of terms is concerned.
Do:
$\frac{6^{p-4q}\times36^{2q+p}}{6^{5p-3q}}$6p−4q×362q+p65p−3q | $=$= | $\frac{6^{p-4q}\times\left(6^2\right)^{2q+p}}{6^{5p-3q}}$6p−4q×(62)2q+p65p−3q |
$=$= | $\frac{6^{p-4q}\times6^{2\left(2q+p\right)}}{6^{5p-3q}}$6p−4q×62(2q+p)65p−3q | |
$=$= | $\frac{6^{p-4q}\times6^{4q+2p}}{6^{5p-3q}}$6p−4q×64q+2p65p−3q | |
$=$= | $\frac{6^{p-4q+4q+2p}}{6^{5p-3q}}$6p−4q+4q+2p65p−3q | |
$=$= | $\frac{6^{3p}}{6^{5p-3q}}$63p65p−3q | |
$=$= | $6^{3p-\left(5p-3q\right)}$63p−(5p−3q) | |
$=$= | $6^{3p-5p+3q}$63p−5p+3q | |
$=$= | $6^{3q-2p}$63q−2p |
Simplify the following, giving your answer with a positive index: $m^9\div m^5\times m^4$m9÷m5×m4
Simplify the following, giving your answer with a positive index: $y^{\frac{6}{5}}\times y^2$y65×y2
Simplify $\frac{b^3\div b^{-7}}{\left(b^{-4}\right)^{-4}}$b3÷b−7(b−4)−4, giving your answer without negative indices.
Fill in the blanks to simplify the given expression.
$\sqrt{m^8}$√m8 | $=$= | $\left(m^8\right)^{\editable{}}$(m8) |
$=$= | $m^{\editable{}\times\frac{1}{2}}$m×12 | |
$=$= | $m^{\editable{}}$m |
The expression $\sqrt[3]{a^2}$3√a2 can also be expressed in index form as $a^{\frac{x}{y}}$axy. What are the values of $x$x and $y$y?
$x$x $=$= $\editable{}$
$y$y $=$= $\editable{}$
Simplify the following, writing without negative indices.
$7p^4q^{-8}\times4p^{-4}q^{-5}$7p4q−8×4p−4q−5
Simplify the following, giving your answer with a single index:
$\frac{3^{-20b-4}\times9^{3b+2}}{81^{-3b-3}}$3−20b−4×93b+281−3b−3