As mentioned in the previous lesson, the Cartesian plane is used to locate points and graphically represent mathematical relationships between two variables. Such relationships are often represented by points connected by lines and curves. The points on the Cartesian plane can be generated from a pattern or an equation relating the variables involved. The points are often presented in a table of values. For example, a table of values might look like the following:
$x$x | $3$3 | $6$6 | $9$9 | $12$12 |
---|---|---|---|---|
$y$y | $10$10 | $19$19 | $28$28 | $37$37 |
Each column of $x$x- and $y$y-values represents a pair of coordinates, or an ordered pair. From this table, for example, $\left(3,10\right),\left(6,19\right),\left(9,28\right),\left(12,37\right)$(3,10),(6,19),(9,28),(12,37) are the coordinate pairs represented.
Let's consider the pattern below. The pattern starts with a triangle made out of matchsticks and continues by adding two additional matchsticks to each subsequent iteration of the pattern.
The table of values for this pattern connects the number of triangles made ($x$x) with the number of matches needed ($y$y).
Number of triangles ($x$x) | $1$1 | $2$2 | $3$3 | $4$4 |
---|---|---|---|---|
Number of matches ($y$y) | $3$3 | $5$5 | $7$7 | $9$9 |
Complete the table for the figures in the given pattern.
Step number ($x$x) | $1$1 | $2$2 | $3$3 | $4$4 | $5$5 | $10$10 |
---|---|---|---|---|---|---|
Number of matches ($y$y) | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
We can also construct a table of values using an equation:
$y=3x-5$y=3x−5
The table of values for this equation connects the $y$y-values that result from substituting in a variety of $x$x-values. Let's complete the table of values below:
$x$x | $1$1 | $2$2 | $3$3 | $4$4 |
---|---|---|---|---|
$y$y |
To substitute $x=1$x=1 into the equation $y=3x-5$y=3x−5, we want to replace all accounts of $x$x with $1$1.
So for $x=1$x=1, we have that:
$y$y | $=$= | $3\left(1\right)-5$3(1)−5 |
$=$= | $3-5$3−5 | |
$=$= | $-2$−2 |
So we know that $-2$−2 must go in the first entry in the row of $y$y-values.
$x$x | $1$1 | $2$2 | $3$3 | $4$4 |
---|---|---|---|---|
$y$y | $-2$−2 |
Next let's substitute $x=2$x=2 into the equation $y=3x-5$y=3x−5.
For $x=2$x=2, we have that:
$y$y | $=$= | $3\left(2\right)-5$3(2)−5 |
$=$= | $6-5$6−5 | |
$=$= | $1$1 |
So we know that $1$1 must go in the second entry in the row of $y$y-values.
$x$x | $1$1 | $2$2 | $3$3 | $4$4 |
---|---|---|---|---|
$y$y | $-2$−2 | $1$1 |
If we substitute the remaining values of $x$x, we find that the completed table of values is:
$x$x | $1$1 | $2$2 | $3$3 | $4$4 |
---|---|---|---|---|
$y$y | $-2$−2 | $1$1 | $4$4 | $7$7 |
Each column in a table of values may be grouped together in the form $\left(x,y\right)$(x,y). The table of values has the following ordered pairs:
Consider the equation $y=7x$y=7x.
What is the value of $y$y when $x=-5$x=−5?
What is the value of $y$y when $x=0$x=0?
What is the value of $y$y when $x=5$x=5?
What is the value of $y$y when $x=10$x=10?
Complete the table of values below:
$x$x | $-5$−5 | $0$0 | $5$5 | $10$10 |
---|---|---|---|---|
$y$y | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
Consider the equation $y=5x+6$y=5x+6.
Complete the table of values below:
$x$x | $-10$−10 | $-5$−5 | $0$0 | $5$5 |
---|---|---|---|---|
$y$y | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
We can plot each ordered pair in our table of values as a point on the Cartesian plane. Consider the following table of values mapped to its respective ordered pairs:
We can plot the ordered pair $\left(a,b\right)$(a,b) by first identifying $x=a$x=a along the $x$x-axis and $y=b$y=b along the $y$y-axis.
Take $\left(3,4\right)$(3,4) as an example. We first identify $x=3$x=3 along the $x$x-axis and imagine a vertical line through this point. Then we identify $y=4$y=4 along the $y$y-axis and imagine a horizontal line through that point. Finally we plot a point where two lines meet, and this represents the ordered pair $\left(3,4\right)$(3,4).
Now that we have plotted the ordered pairs from the table of values, we can draw the graph that passes through these points.
In the example above, the line that passes through these points is given by:
This straight line is the graph of $y=3x-5$y=3x−5 which we used to complete the table of values. From this, we can gain a clear picture of the mathematical relationship represented by the equation.
Consider the equation $y=3x+1$y=3x+1.
Complete the table of values below:
$x$x | $-1$−1 | $0$0 | $1$1 | $2$2 |
---|---|---|---|---|
$y$y | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
Plot the points in the table of values.
Draw the graph of $y=3x+1$y=3x+1.
We just practised graphing from a table of values. Now we will work backwards and complete a table of values from an already constructed graph. Remember that every graph has an $x$x-axis and a $y$y-axis.
The numbers on the $x$x-axis represent the independent variable and are sometimes called the inputs, while the numbers on the $y$y-axis represent the dependent variable and are called the outputs.
Given the following graph, fill in the table.
$x$x | $2$2 | $4$4 | $6$6 | $8$8 | $10$10 | $12$12 | $14$14 |
---|---|---|---|---|---|---|---|
$y$y |
Think: Notice on the graph that when the input ($x$x) is $2$2, the output ($y$y) is $1$1. This corresponds with the ordered pair $\left(2,1\right)$(2,1) on the line.
Do: We can fill this output in the table.
$x$x | $2$2 | $4$4 | $6$6 | $8$8 | $10$10 | $12$12 | $14$14 |
---|---|---|---|---|---|---|---|
$y$y | $1$1 |
We can use this method to fill in the entire table as shown below.
$x$x | $2$2 | $4$4 | $6$6 | $8$8 | $10$10 | $12$12 | $14$14 |
---|---|---|---|---|---|---|---|
$y$y | $1$1 | $2$2 | $3$3 | $4$4 | $5$5 | $6$6 | $7$7 |
Given the following graph, fill in the table.
$x$x | $1$1 | $2$2 | $3$3 | $4$4 |
---|---|---|---|---|
$y$y | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |