In previous chapters we've learnt to simplify expressions involving exponents (or powers) using exponent laws, but all the powers have so far been numbers. In exponentials, we are more interested about what happens if we raise the same base to different powers, so we'll see a lot of algebraic expressions in the powers. But don't worry, the same exponent laws still apply! To remind ourselves they are:
- The product rule: $a^m\times a^n=a^{m+n}$am×an=am+n
- The quotient rule: $a^m\div a^n=a^{m-n}$am÷an=am−n
- The zero exponent rule:$a^0=1$a0=1
- The power of a power rule: $\left(a^m\right)^n=a^{mn}$(am)n=amn
- The negative exponent rule: $a^{-m}=\frac{1}{a^m}$a−m=1am
- The fractional exponent rule: $a^{\frac{m}{n}}=\sqrt[n]{a^m}$amn=n√am
- The fractional base rule: $\left(\frac{a}{b}\right)^m=\frac{a^m}{b^m}$(ab)m=ambm
Be careful when using these rules as the bases have to be the same! For example, if we have an expression such as $3^x\times9^x$3x×9x we can not apply any of these rules as $3\ne9$3≠9. However if we think of $9$9 as two factors of $3$3 multiplied together we can proceed as follows:
| $3^x\times9^x$3x×9x | $=$= | $3^x\times\left(3^2\right)^x$3x×(32)x |
| $=$= | $3^x\times3^{2x}$3x×32x | |
| $=$= | $3^{x+2x}$3x+2x | |
| $=$= | $3^{3x}$33x |
Let's have a look at how to simplify (simplest exponential form) some more complicated examples!
Examples
question 1
Simplify the expression $\frac{6^{p-4q}\times36^{2q+p}}{6^{5p-3q}}$6p−4q×362q+p65p−3q
Think: First make sure all terms have the same base and be careful of order of operations when subtraction is concerned
Do:
| $\frac{6^{p-4q}\times36^{2q+p}}{6^{5p-3q}}$6p−4q×362q+p65p−3q | $=$= | $\frac{6^{p-4q}\times\left(6^2\right)^{2q+p}}{6^{5p-3q}}$6p−4q×(62)2q+p65p−3q |
| $=$= | $\frac{6^{p-4q}\times6^{2\left(2q+p\right)}}{6^{5p-3q}}$6p−4q×62(2q+p)65p−3q | |
| $=$= | $\frac{6^{p-4q}\times6^{4q+2p}}{6^{5p-3q}}$6p−4q×64q+2p65p−3q | |
| $=$= | $\frac{6^{p-4q+4q+2p}}{6^{5p-3q}}$6p−4q+4q+2p65p−3q | |
| $=$= | $\frac{6^{3p}}{6^{5p-3q}}$63p65p−3q | |
| $=$= | $6^{3p-\left(5p-3q\right)}$63p−(5p−3q) | |
| $=$= | $6^{3p-5p+3q}$63p−5p+3q | |
| $=$= | $6^{3q-2p}$63q−2p |
question 2
If $6^x=13$6x=13, find the value of $6^{x+1}$6x+1.
question 3
Use exponent laws to simplify the ratio $\left(0.3\right)^a:\left(0.3\right)^{a+2}$(0.3)a:(0.3)a+2 to a ratio of whole numbers.