UK Secondary (7-11)
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Solve applications of quadratics

Interactive practice questions

An object launched from the ground has a height (in feet) after $t$t seconds that is modelled by the graph.

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a

What is the maximum height of the object?

$576$576 feet

A

$6$6 feet

B

$24$24 feet

C

$600$600 feet

D

$576$576 feet

A

$6$6 feet

B

$24$24 feet

C

$600$600 feet

D
b

After how many seconds is the object at its maximum height?

$13$13 seconds

A

$4$4 seconds

B

$8$8 seconds

C

$6$6 seconds

D

$13$13 seconds

A

$4$4 seconds

B

$8$8 seconds

C

$6$6 seconds

D
c

How many seconds after launch does the object return to the ground?

$0$0 seconds

A

$6$6 seconds

B

$13$13 seconds

C

$12$12 seconds

D

$0$0 seconds

A

$6$6 seconds

B

$13$13 seconds

C

$12$12 seconds

D
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On Earth, the equation $d=4.9t^2$d=4.9t2 is used to find the distance (in metres) an object has fallen after $t$t seconds. (Assuming no air resistance or buoyancy) 

The distance a freely falling object falls is modelled by the formula $d=16t^2$d=16t2, where $d$d is the distance in feet that the object falls and $t$t is the time elapsed in seconds.

On the moon, the equation $d=0.8t^2$d=0.8t2 is used to approximate the distance an object has fallen after $t$t seconds. (Assuming no air resistance or buoyancy). On Earth, the equation is $d=4.9t^2$d=4.9t2.

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