Systems of Equations

UK Secondary (7-11)

Number and nature of solutions to linear systems

Lesson

So far we've only had to solve equations with one variable. We know that rearranging $x+2=5$`x`+2=5 will give us a unique answer of $3$3 for $x$`x`, but what happens when we have more than one variable in our equation?

Consider $x+y=6$`x`+`y`=6. This could have the solution $x=2$`x`=2 & $y=4$`y`=4, or another solution of $x=40$`x`=40 & $y=-34$`y`=−34. In fact, there are infinitely many solutions to this equation. Just pick any value for $x$`x`, and then use the equation to find the corresponding value of $y$`y` required to make the equation hold true.

If we have **two **equations with the same two variables in them ($x$`x` and $y$`y`), then we call them a system of equations. They are also commonly referred to as simultaneous equations.

We might be interested in finding a common pair of $x$`x` and $y$`y` values that satisfies both of these equations simultaneously. If we can find a values of $x$`x` and $y$`y` that successfully do this, then we will have found a unique solution to our system.

On a coordinate plane, the solution is represented by the point of intersection of the two equations' graphs (where the two graphs cross over). So the $x$`x` and $y$`y` values of our solution will take the form of coordinates of the intersection point $\left(x,y\right)$(`x`,`y`).

With this in mind, how many solutions should be possible for each set of two simultaneous linear equations?

Number of solutions to a system

If the lines representing the two equations *are not* parallel, then there should be **exactly one** point of intersection between them (as pictured above). Have a think about why this is true.

If the lines *are* parallel and distinct, then there **will not** be any points of intersection between them. This means no corresponding $x$`x` and $y$`y` values satisfy both equations simultaneously.

The final case to consider is when two different equations have the same graphical representation. For example, if the graphs of $x+y=5$`x`+`y`=5 and $2x+2y=10$2`x`+2`y`=10 were placed on the same set of axes, we would end up with two lines lying perfectly on top of one another. So every point on the line is a point of intersection, meaning there is **infinitely many** solutions to this system of equations.

So where might this system of equations come from, and why is it important to know how many solutions it has?

Leah got a quote from two photographers for an event. Photographer $A$`A` charges a $\$48$$48 booking fee plus $\$17$$17 per hour of the event, whilst photographer $B$`B` has a $\$28$$28 booking fee and charges $\$21$$21 per hour. Form a system of equations that represents this information, and determine how many solutions the system will have.

**Think: **Which quantities from this situation will the $x$`x` and $y$`y` represent? Are any of them related to one another?

**Do:** The duration of the event is variable and will affect the overall cost of the photographer, so lets represent the duration of the event with $x$`x` and the total cost of the photographer for the event with $y$`y`. Then we could form one equation relating the duration and the cost of the event for each photographer as follows:

$y$y |
$=$= | $48+17x$48+17x |
$(A)$(A) |

$y$y |
$=$= | $28+21x$28+21x |
$(B)$(B) |

We've now formed an appropriate system of equations, so how can we tell how many solutions it will have?

Looking at the coefficient of $x$`x` in each equation tells us the lines representing them have different gradients, so looking at the green summary box from earlier in the lesson, we know the system will have exactly one solution.

**Reflect:** Since the lines representing these cost equations have a point of intersection, this means there will be a duration of the event for which the photographers cost the same. More interestingly, this implies that the cheapest option for photographer will depend on the length of the event.

How can we know whether a given ordered pair is a solution of a system of equations? Select all that apply.

If substituting the pair into each equation results in a true statement.

AIf substituting the pair into each equation eliminates the variables.

BIf substituting the pair into each equation results in zero.

CIf substituting the pair into each equation makes the left-hand side equal to the right-hand side.

DIf substituting the pair into each equation results in a true statement.

AIf substituting the pair into each equation eliminates the variables.

BIf substituting the pair into each equation results in zero.

CIf substituting the pair into each equation makes the left-hand side equal to the right-hand side.

D

We are going to determine whether the point $\left(2,-2\right)$(2,−2) is a solution of the system of equations:

$2x+3y=-2$2`x`+3`y`=−2

$4x+3y=5$4`x`+3`y`=5

Using the first equation, $2x+3y=-2$2

`x`+3`y`=−2, find the value of $y$`y`when $x=2$`x`=2.Now using the second equation, $4x+3y=5$4

`x`+3`y`=5, find the value of $y$`y`when $x=2$`x`=2.Hence, is $\left(2,-2\right)$(2,−2) a solution of the system?

Yes

ANo

BYes

ANo

B

Gwen has a total of $£11500$£11500, which she has put into two accounts. She has four times as much money in her savings account as in her checking account.

Let $x$`x` represent the amount in her checking account and let $y$`y` represent the amount in her savings account.

Write a system of two equations that describes all the information provided, giving both equations on the same line separated by a comma. You do

**not**need to solve the system.