UK Primary (3-6) Divide a 3 digit number by a 1 digit number resulting in a remainder
Lesson

When we divide a three digit number, such as 460, by a one digit number, perhaps 8, we may find we have some left over.  To help us with this division, or sharing, we can use 'chunking' to work out our answer in sections.  We are then left with any amounts that can't be shared.

#### Worked Examples

##### Question 1

Calculate $465\div2$465÷​2 by doing the following.

1. Calculate $400\div2$400÷​2.

2. Calculate $60\div2$60÷​2.

3. Calculate $4\div2$4÷​2.

4. Using the fact that $465=400+60+4+1$465=400+60+4+1, fill in the boxes with the missing numbers.

$2$2 goes into four hundred and sixty five $\editable{}$ times with a remainder of $\editable{}$

##### Question 2.

Calculate $769\div3$769÷​3 by doing the following.

1. Calculate $600\div3$600÷​3.

2. Calculate $150\div3$150÷​3.

3. Calculate $18\div3$18÷​3.

4. Using the fact that $769=600+150+18+1$769=600+150+18+1, fill in the boxes with the missing numbers.

$3$3 goes into seven hundred and sixty nine $\editable{}$ times with a remainder of $\editable{}$

##### Question 3

Calculate $904\div6$904÷​6 by doing the following.

1. First, calculate $900\div6$900÷​6

2. Fill in the boxes with the missing numbers.

$6$6 goes into nine hundred and four $\editable{}$ times with a remainder of $\editable{}$