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Q: How do you factor 8x cubed plus one?

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Related questions

(8x + 9)(3x^2 - 1)

(2x + 5)(4x2 - 10x + 25)

The answer is (2x^2+3)(4x+1)

2(x + 3)(x^2 + 4)

2x^2y^3(4x^2 - 3xy + 1)

the GCF is 8x

(2x - 1)(4x2 + 2x + 1)

(2x + 5)(4x^2 - 10x + 25)

-8x + 3x2 - 3

8x(x2-x+1)

x2 + 8x + 15 = (x + 3)(x + 5)

x2 + 8x + 15 = (x + 3) (x + 5).

That does not factor neatly.

This is not factor-able.

It is not possible to give a sensible answer to this question. The greatest common factor (GCF) refers to a factor that is COMMON to two or more numbers. You have only one expression, 8x+16, in the question!

2x^2(x - 2)(x - 2)

(x + 1)(3x + 5)

(x + 6)(x + 2)

9x2 + 8x - 1 = (9x - 1)(x + 1)

x2-8x+15 = (x-3)(x-5)

8x(x+9)

(x + 5)(x + 8)

x2 + 8x = x(x+8)

x2-8x+16 = (x-4)(x-4) when factored

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