In this example, we would say that the payout associated with the event that the coin lands “heads” is $\$20$$20, and the payout associated with “tails” is $\$0$$0.

On of the most common ways of evaluating if this is a good deal or not is to calculate the expected value.

The expected value is the average of all possible outcomes, adjusted for the probability that each outcome will occur.

If we use X to indicate the possible payouts then,

The heads scenario: $X_H=\$20$XH=$20

The tails scenario: $X_T=\$0$XT=$0

The expected value = probability of heads x payout for a head + probability for tails x payout for tails

$E(X)=$E(X)= $P(H)$P(H) × $X_H$XH $+P(T)$+P(T) × $X_T$XT

$E(X)=$E(X)= $\frac{1}{2}\times20+\frac{1}{2}\times0$12×20+12×0

$E(X)=$E(X)= $10$10

Later that day, whilst you are out wandering, you bump into your Uncle. You ask him for the $\$20$$20. Instead of just giving you the money he offers the following deal. I will roll a dice and give you $\$3$$3 for every spot on the side of the dice.

Using the expected value is one way of comparing the two offers. For this offer we have the following payout options:

$X_1=\$3$X1=$3

$X_2=\$6$X2=$6

$X_3=\$9$X3=$9

$X_4=\$12$X4=$12

$X_5=\$15$X5=$15

$X_6=\$18$X6=$18

Multiplying each by the respective probabilities gives

$E(X)$`E`(`X`)	$=$=	$\frac{1}{6}\times X_1+\frac{1}{6}\times X_2+\frac{1}{6}\times X_3+\frac{1}{6}\times X_4+\frac{1}{6}\times X_5+\frac{1}{6}\times X_6$16×`X`1+16×`X`2+16×`X`3+16×`X`4+16×`X`5+16×`X`6
	$=$=	$\frac{1}{6}\times3+\frac{1}{6}\times6+\frac{1}{6}\times9+\frac{1}{6}\times12+\frac{1}{6}\times15+\frac{1}{6}\times18$16×3+16×6+16×9+16×12+16×15+16×18
	$=$=	$\frac{1}{2}+1+\frac{9}{6}+2+\frac{15}{6}+3$12+1+96+2+156+3
	$=$=	$\$10.50$$10.50

So simply comparing the expected value of the offers the uncles deal appears to be a slightly better one. Of course, you might like to risk the knowledge of definitely getting at least $\$3$$3 from your uncle for the chance of the $\$20$$20 from you grandmother.

Worked Examples

QUESTION 1

$Han$ buys a $£1500$ laptop and can also purchase a $3$ -year extended warranty on the laptop. The manufacturer's historical records show that the probability of the laptop needing repair, which costs $£403$ on average, is $0.06$ in the $3$ -year period after purchase and the probability of the laptop needing to be replaced is $0.03$ .

Calculate the expected value of the extended warranty.
If the warranty costs $£155$ , is the warranty fair value?
Yes
A
No
B

QUESTION 2

$Dave$ and $Mae$ are fighting over who gets to watch the TV at home. They decide to settle their differences by rolling a die. $Dave$ rolls first. He wins control over the TV if he rolls a number greater than four. If he doesn't win, $Mae$ gets her chance and wins if she rolls a prime number. If she doesn't roll a prime number, their parents take the remote and nobody wins.

What is $Dave$ 's chance of winning?
What is $Mae$ 's probability of winning?
Is this a fair way to settle the argument for both $Dave$ and $Mae$ ?
Yes
A
No
B

QUESTION 3

Given the following options:

(A) a sure gain of $£500$£500

(B) a $50$50% chance of gaining $£1000$£1000 and a $50$50% chance of gaining nothing

Calculate the financial expectation of Option A.
Calculate the financial expectation of Option B.
Which option has greater variation?
Option A
A
Option B
B

Expectation and Fair Value

That's not fair!

Worked Examples

QUESTION 1

QUESTION 2

QUESTION 3

What is Mathspace

About Mathspace