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CanadaON
Grade 10

Solving equations by iteration (Investigation)

Lesson

In mathematics we learn methods to solve simple equations such as  2 x + 4 = 5 and more difficult equations such as x^{2} + 6 x + 8 = 0.  But how can we find the solution for more complex equations such as x^{4} - 2 x = 0

Guess and Check

We could guess the solution for x , substitute it into the equation then evaluate the equation to check if it is a true statement.  If it is not true we will try another value for x.

Example:

Solve x^{4} - 2 x = 0

Guess x = 1  
Check does 1^{4} - 2 = 0  
  - 1 = 0 not true
Guess x = 2
Check does 2^{4} - 2 \times 2 = 0
  16 - 4 = 0
 
  12 = 0

What is the problem with this process and what do we need to consider?  What are suitable values to try for x?

Another possible method could be to write x as a function of x  ,f x .  The equation can be rearranged as follows:  x = \frac{1}{2} x^{4}

In this case we can try a value for x, evaluate a new value forx and then check if our new value is close to the old value.

Pick an initial guess for x and call this x_0  (are there any restrictions for values of x?)

x_{1}=\frac{1}{2}x{_{0}}^{4} , evaluate for x_1

Then use x_1as the next guess for x

x_{2}=\frac{1}{2}x{_{1}}^{4} , evaluate for x_2

 

Write an algorithm for this process

Solution

  • Make an initial guess for x
  • Evaluate  \frac{1}{2} x_4  to calculate new value for x
  • Repeat until x_{i + 1} - x_i < 0.0001
  • Stop

 

Draw a flowchart for this process

Solution

 

We can use an excel spreadsheet to perform these iteration calculations

The spreadsheet table could look like this

x_i x_i + 1
1                              *                              
**  
   
  • What cell formula should be written in the yellow cell to calculate our new value for x?
  • What cell formula should be written in the red cell to calculate our new value for x?
  • Copy the formulas in the red and yellow cells to the cells below by using the drag and fill function
  • What does the table look like when the first value for x tried is 1?
x_i + 1 x_1
1 0.5
0.5 0.03125
0.03125                0.0000004768371582

 

  • What does the table look like when the first value for x tried is 10?
x_i + 1 x_i
10 5000
5000 312500000000000
312500000000000 4.76837E+57
4.76837E+57 2.58494E+230

Are the values of x converging (approaching a particular number) or diverging (not approaching a number - getting further from each successive value for x)?  Will the loop in our flowchart /program ever terminate?  This method of solving the equation has not been successful.

 
  • Can the original equation have a different arrangement of the form x =f\left(x\right) ?   What is this?
 

The original equation can be rearranged as follows: \sqrt[4]{2x_{i}} 

Change your flowchart for this new formula

 

Set up a spreadsheet in excel using this new formula and use the process of iteration to calculate successive values of x. Fill in the cells below.

x \sqrt[4]{2x_{i}}
                         1  
   
   
   
   
   
   
   
   
   

Solution

x \sqrt[4]{2x_{i}}
1 1.189207115
1.189207115 1.241857812
1.241857812 1.255380757
1.255380757 1.25878444
1.25878444 1.259636801
1.259636801 1.259849982
1.259849982 1.259903282
1.259903282 1.259916608
1.259916608 1.259919939
   
  • Are the values of x converging or diverging?  This method of solving the equation has been successful. 

The solution for x correct to 4 decimal places is 1.2599

  • What happens if we try a different value for the original value of x?  Lets try the value 10.

 

Solution

x \sqrt[4]{2x_{i}}
10 2.114742527
2.114742527 1.434075029
1.434075029 1.30136903
1.30136903 1.270157613
1.270157613 1.26247243
1.26247243 1.260558411
1.260558411 1.26008036
1.26008036 1.259960876
1.259960876 1.259931006
1.259931006 1.259923539
1.259923539 1.259921672

The solution for x correct to 4 decimal places is 1.2599

 

 

 

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