NZ Level 8 (NZC) Level 3 (NCEA) [In development]
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Phase shifts for sine and cosine

Interactive practice questions

Consider the given graph of $y=\cos\left(x+\frac{\pi}{2}\right)$y=cos(x+π2).

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a

What is the amplitude of the function?

b

How can the graph of $y=\cos x$y=cosx be transformed into the graph of $y=\cos\left(x+\frac{\pi}{2}\right)$y=cos(x+π2)?

By reflecting it about the $x$x-axis, and then translating it horizontally $\frac{\pi}{2}$π2 units to the left.

A

By reflecting it about the $x$x-axis, and then translating it horizontally $\frac{\pi}{2}$π2 units to the right.

B

By translating it horizontally $\frac{\pi}{2}$π2 units to the right.

C

By changing the period of the function.

D

By translating it horizontally $\frac{\pi}{2}$π2 units to the left.

E

By reflecting it about the $x$x-axis, and then translating it horizontally $\frac{\pi}{2}$π2 units to the left.

A

By reflecting it about the $x$x-axis, and then translating it horizontally $\frac{\pi}{2}$π2 units to the right.

B

By translating it horizontally $\frac{\pi}{2}$π2 units to the right.

C

By changing the period of the function.

D

By translating it horizontally $\frac{\pi}{2}$π2 units to the left.

E
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Consider the function $f\left(x\right)=\sin x$f(x)=sinx and $g\left(x\right)=\sin\left(x-\frac{\pi}{2}\right)$g(x)=sin(xπ2).

Consider the function $f\left(x\right)=\cos x$f(x)=cosx and $g\left(x\right)=\cos\left(x-\frac{\pi}{2}\right)$g(x)=cos(xπ2).

Consider the function $y=\sin\left(x-\frac{\pi}{2}\right)$y=sin(xπ2).

Outcomes

M8-2

Display and interpret the graphs of functions with the graphs of their inverse and/or reciprocal functions

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