The distance a particular animal can see to the horizon is modelled by $d\left(x\right)=\sqrt{\frac{5x}{2}}$`d`(`x`)=√5`x`2, where $x$`x` is the number of feet the animal is above sea level and $d\left(x\right)$`d`(`x`) is in miles.

a

If the animal is lying on a rock that is $32$32 feet above the water, how far can it see?

Give an exact answer in simplest form.

b

Hence find the distance that the animal can see to the nearest tenth of a mile.

Easy

Approx 3 minutes

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