Find the measure in degrees of the acute angle satisfying $\sin\theta=\frac{1}{\sqrt{2}}$sinθ=1√2.

Find the measure of the angle satisfying $\cos\theta=\frac{1}{\sqrt{2}}$cosθ=1√2 for $0^\circ<\theta<90^\circ$0°<θ<90°.

Find the measure in degrees of the acute angle satisfying $\tan\theta=\sqrt{3}$tanθ=√3.

Find the measure in degrees of the acute angle satisfying $5\sqrt{2}\sin\theta-5=0$5√2sinθ−5=0.

Form and use linear, quadratic, and simple trigonometric equations

Apply algebraic methods in solving problems