In trigonometry the cosine rule relates the lengths of the sides and the cosine of one of its angles.
The Law of Cosines is useful in finding:
ABC is a triangle with side lengths $BC=a$BC=a , $CA=b$CA=b and $AB=c$AB=c and the opposite angles of the sides are respectively angle $A$A, angle $B$B and angle $C$C.
$a^2=b^2+c^2-2bc\cos A$a2=b2+c2−2bccosA
$b^2=a^2+c^2-2ac\cos B$b2=a2+c2−2accosB
$c^2=a^2+b^2-2ab\cos C$c2=a2+b2−2abcosC
Notice that Pythagoras' Theorem $a^2=b^2+c^2$a2=b2+c2 makes an appearance in the Cosine Rule: $a^2=b^2+c^2-2bc\cos A$a2=b2+c2−2bccosA
Find angle $B$B in the triangle.
Think: All three side lengths are known, so I can apply the cosine rule. The unknown angle B appears opposite side $b=3$b=3.
$b^2$b2 | $=$= | $a^2+c^2-2ac\cos B$a2+c2−2accosB |
$3^2$32 | $=$= | $5^2+6^2-2\times5\times6\cos B$52+62−2×5×6cosB |
$9$9 | $=$= | $25+36-60\cos B$25+36−60cosB |
$9-61$9−61 | $=$= | $-60\cos B$−60cosB |
$\frac{-52}{-60}$−52−60 | $=$= | $\cos B$cosB |
$\cos B$cosB | $=$= | $0.866667$0.866667 |
$B$B | $=$= | $29.9^\circ$29.9° to $1$1 decimal place |
Find the value of $x$x in the diagram.
Think: The first thing I always do is identify which side is opposite the given angle. This side is the subject of the formula. To find out which other values we are given I label the sides and angles using $a$a,$b$b and $c$c .
Do:
I add the following labels to the triangle:
So I want to find the value of $c$c.
$c^2$c2 | $=$= | $a^2+b^2-2ab\cos C$a2+b2−2abcosC |
$c^2$c2 | $=$= | $8^2+11^2-2\times8\times11\cos39^\circ$82+112−2×8×11cos39° |
$c^2$c2 | $=$= | $64+121-176\cos39^\circ$64+121−176cos39° |
$c^2$c2 | $=$= | $48.22$48.22 |
$c$c | $=$= | $6.94$6.94 |
The following interactive demonstrates that the cosine rule holds regardless of the angles or size and shape of the triangle.
Find the length of $a$a using the cosine rule.
Round your answer to two decimal places.
Find the length of $c$c using the cosine rule.
Round your answer to two decimal places.
Apply trigonometric relationships, including the sine and cosine rules, in two and three dimensions
Apply trigonometric relationships in solving problems