Solve applications of quadratics
Interactive practice questions
An object launched from the ground has a height (in feet) after $t$t seconds that is modelled by the graph.
What is the maximum height of the object?
$576$576 feet
$6$6 feet
$24$24 feet
$600$600 feet
After how many seconds is the object at its maximum height?
$13$13 seconds
$4$4 seconds
$8$8 seconds
$6$6 seconds
How many seconds after launch does the object return to the ground?
$0$0 seconds
$6$6 seconds
$13$13 seconds
$12$12 seconds
On Earth, the equation $d=4.9t^2$d=4.9t2 is used to find the distance (in metres) an object has fallen after $t$t seconds. (Assuming no air resistance or buoyancy)
The distance a freely falling object falls is modelled by the formula $d=16t^2$d=16t2, where $d$d is the distance in feet that the object falls and $t$t is the time elapsed in seconds.
On the moon, the equation $d=0.8t^2$d=0.8t2 is used to approximate the distance an object has fallen after $t$t seconds. (Assuming no air resistance or buoyancy). On Earth, the equation is $d=4.9t^2$d=4.9t2.