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AustraliaVIC
VCE 11 General 2023

11.09 Circles, sectors and arc length

Lesson

Circumference and arc length of a circle

The circumference of a circle is the distance around the edge of a circle. In other words, 'circumference' is a specific term for the perimeter of the circle,C=2\pi r where C is the circumference and r is the radius of a circle.

For example, if the radius of a circle is 8\text{ cm}, the circumference, C=2\pi r=2\times \pi \times 8=50.3\text{ cm}(rounded to one decimal place).

The image shows a circle arc and a sector. Ask your teacher for more information.

As the arc of a circle is a fraction of the edge of a circle, we can calculate its arc length s using a variation of the circumference of a circle formula.

A semicircular arc.

Imagine first that the arc length that we want is half of the edge of the circle, then we could take half the circumference and get s=\dfrac{1}{2} \times 2 \pi r.

A quarter circle arc.

What if we wanted a quarter of the edge? Then the arc length would be s=\dfrac{1}{4} \times 2 \pi r.

What if we want a different fraction? Particularly, the fraction created by using an angle \theta. Then we would use s=\dfrac{\theta}{360\degree}\,2\pi r.

If \theta is the angle at the centre of the circle, measured in degrees and subtended by an arc, then the arc length can be calculated using the formula: \begin{aligned}s&=\dfrac{\theta}{360\degree}\times 2\pi r \\ &= r \times \dfrac{\pi}{180\degree}\times \theta \end{aligned}

When finding the perimeter of a sector, don't forget to add the lengths of the straight edges to the arc length. \text{Perimeter of a Sector} = \text{Arc Length} + 2 r

Exploration

Manipulate this applet by moving the point on the circle to see the relationship between the contained angle and the arc length.

Loading interactive...

For any angle, \theta, the arc length is always given by \dfrac{\theta}{360\degree} \times 2 \pi r.

Examples

Example 1

Find the length of the arc in the figure correct to one decimal place.

A sector with a radius of 74 kilometres and an angle of 50 degrees.
Worked Solution
Create a strategy

Use the formula for an arc: s=\dfrac{\theta}{360\degree} \times 2\pi r

Apply the idea
\displaystyle s\displaystyle =\displaystyle \dfrac{50\degree}{360\degree} \times 2 \pi \times 74Substitute \theta=50,\,r=74
\displaystyle =\displaystyle 64.6\text{ km}Simplify

Example 2

If the arc formed by two points on a sphere with a radius of 2 \text{ m} subtends an angle of 37\degree at the centre, find the length of the arc correct to two decimal places.

Worked Solution
Create a strategy

Use the formula for an arc: s=\dfrac{\theta}{360\degree} \times 2\pi r

Apply the idea
\displaystyle \text{Arc length}\displaystyle =\displaystyle \dfrac{37\degree}{360\degree} \times 2 \pi \times 2Substitute \theta=37,\,r=2
\displaystyle =\displaystyle 1.29 \text{ m}Simplify
Idea summary

'Circumference' is a specific term for the perimeter of the circle and is given by the formula:

\displaystyle C=2\pi r
\bm{C}
is the circumference
\bm{r}
is the radius of the circle

The arc length s of a sector is given by the formula:

\displaystyle s =\dfrac{\theta}{360\degree} \times 2 \pi r
\bm{r}
is the radius of the circle

Area of a sector

The area of a full circle, measured in square units, can be found using the following formula: \text{Area of a circle}=\pi r^2

Given that the area of a circle is \pi r^2 thearea of a sector is some fraction of that full area \dfrac{\theta}{360\degree}\times \pi r^2.

There is a minor sector and a major sector associated with any given angle at the centre. The area of the corresponding sector can be found by replacing \theta with 360\degree-\theta in the formula for the area of a sector, to become \dfrac{360\degree-\theta}{360\degree}\times \pi r^2. Notice this simplifies to \pi r^2-\dfrac{\theta }{360}\times \pi r^2, i.e. subtracting the area of the original sector from the area of the whole circle.

A sector with an acute angle theta and radius R.

We can make a formula for the area of any sector depending on the angle \theta that subtends the arc at the centre.

A sector with a reflex contained angle as theta and radius r.

A sector with contained angle \theta corresponds to a fraction \dfrac{\theta}{360\degree} of a full circle and so its area is given by: A = \dfrac{\theta}{360\degree} \times \pi r^2

Examples

Example 3

Find the area of the following sector of a circle. Round your answer to one decimal place.

A sector with a radius of 13 centimetres and an contained angle of 121 degrees.
Worked Solution
Create a strategy

Use the formula for the area of sector:\text{ Area}=\dfrac{\theta}{360\degree}\times\pi r^{2}

Apply the idea
\displaystyle \text{Area}\displaystyle =\displaystyle \dfrac{121\degree}{360\degree}\times \pi \times 13^{2}Substitute r=13 and \theta =121
\displaystyle =\displaystyle 178.5\text{ cm}^{2}Evaluate and round

Example 4

Consider the sector below.

A quarter circle with a radius of 96.4 millimetres.
a

Calculate the perimeter. Give your answer correct to one decimal place.

Worked Solution
Create a strategy

Add the two radii and the arc length.

Apply the idea

We write the equation as \text{Perimeter}=2r + \dfrac{\theta}{360\degree}\times 2\pi r,

\displaystyle \text{Perimeter}\displaystyle =\displaystyle 2\times 96.4 + \dfrac{90\degree}{360\degree}\times 2\pi \times 96.4Substiute r=96.4,\,\theta =90
\displaystyle =\displaystyle 344.2 \text{ mm}Evaluate
b

Calculate the area. Give your answer correct to four decimal places.

Worked Solution
Create a strategy

Use the formula for the area of sector:\text{ Area}=\dfrac{\theta}{360\degree}\times\pi r^{2}

Apply the idea
\displaystyle \text{Area}\displaystyle =\displaystyle \dfrac{90\degree}{360\degree}\times \pi \times 96.4^{2}Substitute r=96.4 and \theta =90
\displaystyle =\displaystyle 7298.6737\text{ mm}^{2}Evaluate and round
Idea summary

The area of a full circle can be found using the following formula:

\displaystyle \text{Area of a circle}=\pi r^2
\bm{r}
is the radius

The area of the sector with contained angle \theta can be found using:

\displaystyle A = \dfrac{\theta}{360\degree} \times \pi r^2
\bm{\theta}
is the contained angle of the sector
\bm{r}
is the radius

Outcomes

U2.AoS4.12

use quadrilaterals, circles and composite shapes including arcs and sectors in practical situations

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