Learning objective
The identity matrix, denoted by I, is a special type of square matrix that has 1s on its main diagonal (from the top left to the bottom right) and 0s elsewhere. When a square matrix is multiplied by its corresponding identity matrix, the result is the original matrix.
Identity matrix of a 2 \times 2 matrix \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}
The determinant of a square matrix is a scalar value that has several important properties and applications, such as determining the invertibility of a matrix and finding the area of a parallelogram formed by two vectors. The determinant of a 2 \times 2 matrix A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} can be found using the formula \det(A) = |A| =ad -bc.
For example, the determinant of A = \begin{bmatrix} 4 & 2 \\ 3 & 5 \end{bmatrix} would be \det(A) = (4)(5)-(2)(3) = 20 - 6 = 14.
For the matrix A = \begin{bmatrix} a & b \\ c & d \end{bmatrix}, a parallelogram can be formed with the vertices (0,\,0),\, (a,\, b)\,(c,\, d), and (a+b,\, c+d). The area of this parallelogram can be found by taking the non-zero absolute value of the determinant. If \det(A) = 0, then the vectors formed by the column and row vectors are parallel.
Example: Compute the area of the parallelogram spanned by the matrix A = \begin{bmatrix} 2 & 6 \\ 6 & 0 \end{bmatrix}. The visual of the parallelogram is represented below.
The area can be found with the formula: |\det(A)| = |ad - bc|.
\displaystyle |\det(A)| | \displaystyle = | \displaystyle |(2)(0) - (6)(6)| | Substitute a=2,\,d=0,\,b=6 and c=6 |
\displaystyle = | \displaystyle |0-36| | Evaluate the multiplication | |
\displaystyle = | \displaystyle |-36| | Evaluate the subtraction | |
\displaystyle = | \displaystyle 36 | Evaluate |
In the next section, we will explore how to use the determinant to determine the inverse of a matrix. A square matrix A has an inverse if and only if its determinant, \det(A) \neq 0.
Find the determinant of the following matrices:
\begin{bmatrix} 5 & 3 \\ 1 & 7 \end{bmatrix}
\begin{bmatrix} 8 & 3 \\ -4 & 2 \end{bmatrix}
Determine the area of the parallelogram formed by the column vectors of the matrix A = \begin{bmatrix} 7 & 2 \\ 5 & 9 \end{bmatrix}.
An identity matrix is a square matrix with 1s on the diagonal from the top left to the bottom right and 0s everywhere else, and it doesn't change a matrix when multiplied together. The determinant of a 2 \times 2 matrix A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} is calculated as ad - bc, and its absolute value can be used to find the area of a parallelogram formed by the column or row vectors of the matrix.
The inverse of a square matrix, when it exists, is the matrix that, when multiplied by the original matrix, results in the identity matrix \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}. This relationship can be described as AA^{-1}=I where A is a 2 \times 2 matrix, A^{-1} is the inverse of the matrix, and I is the identity matrix. For the 2 \times 2 matrix A = \begin{bmatrix} a & b \\ c & d \end{bmatrix}, the inverse of the matrix is determined by A^{-1}=\dfrac{1}{\text{det}(A)}\begin{bmatrix} d & -b \\ -c & a \end{bmatrix}.
A square matrix A is invertible if and only if its determinant, \text{det}(A) \neq 0. If \text{det}(A) = 0, the matrix is called singular or non-invertible.
Determine if the following matrix has an inverse: \begin{bmatrix} 8 & 3 \\ -4 & 2 \end{bmatrix}
Given the matrix: A = \begin{bmatrix} 9 & -6 \\ -11 & 8 \end{bmatrix}
Determine the inverse of the matrix.
Find AA^{-1}.
The inverse of a 2\times 2 matrix exists if its determinant is non-zero, and when multiplied by its inverse, a matrix results in the identity matrix. To find the inverse of a 2\times 2 matrix, you can use the formula A^{-1} = \dfrac{1}{\text{det}(A)}\begin{bmatrix} d & -b \\ -c & a \end{bmatrix}.