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VCE 11 Methods 2023

3.04 Cubic equations

Lesson

Similar to solving quadratics, there are several methods to choose between when solving cubic equations:

  • Solve using algebraic manipulation - For cubics such as $2x^3+16=0$2x3+16=0.
  • Factorise - Fully factorising the cubic and then using the null factor law to solve. If $a\times b=0$a×b=0 then either $a=0$a=0 or $b=0$b=0.
  • Technology - Once the important information from a question has been extracted and formed into an equation, use technology to solve the equation graphically or algebraically. 

 

When factorising a cubic polynomial, recall that this can be done by:

  • using the highest common factor
  • identifying special forms such as the sum and difference of cubes
  • finding a single factor, then using division to establish the remaining quadratic. Employ any of the factorising methods for quadratics to fully factorise the polynomial

 

Practice questions

Question 1

Solve the equation $x^3=-8$x3=8.

QUESTION 2

Solve the equation $x^3-49x=0$x349x=0.

  1. State the solutions on the same line, separated by a comma.

QUESTION 3

The cubic $P\left(x\right)=x^3-2x^2-5x+6$P(x)=x32x25x+6 has a factor of $x-3$x3.

  1. Solve for the roots of the cubic. If there is more than one root, state the solutions on the same line separated by commas.

Outcomes

U1.AoS2.10

factorisation patterns, the quadratic formula and discriminant, the remainder, factor and rational root theorems and the null factor law

U1.AoS2.7

solution of polynomial equations of low degree, numerically, graphically and algebraically, including numerical approximation of roots of simple polynomial functions using the bisection method algorithm

U1.AoS2.17

use algebraic, graphical and numerical approaches, including the factor theorem and the bisection method algorithm, to determine and verify solutions to equations over a specified interval

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