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VCE 12 Methods 2023

6.05 Optimisation

Interactive practice questions

A potato farmer finds that the yield per square metre when spacing his plants between $0.5$0.5 m and $3.0$3.0 m approximates the following equation:

$y=-\frac{x^2}{4}+\frac{7x}{20}$y=x24+7x20

a

Find $\frac{dy}{dx}$dydx.

b

For what value of $x$x is $\frac{dy}{dx}$dydx equal to $0$0?

c

What is the maximum possible yield?

Round your answer to two decimal places.

Easy
4min

A parabolic satellite dish is pointing straight up. Along a cross-section that passes through the centre of the dish, the height above ground is given by the following equation:

$y=\frac{1}{100}\left(x^2-100x\right)+50$y=1100(x2100x)+50

Easy
3min

A function $f:\left[-7,5\right]\to\mathbb{R}$f:[7,5] is given by $f\left(x\right)=-6x^2-12x+90$f(x)=6x212x+90.

Easy
4min

A function $f:\left[3,8\right]\to\mathbb{R}$f:[3,8] is given by $f\left(x\right)=2x^2-2x-24$f(x)=2x22x24.

Easy
3min
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Outcomes

U34.AoS1.13

the features which enable the recognition of general forms of possible models for data presented in graphical or tabular form

U34.AoS3.15

evaluate derivatives of basic, transformed and combined functions and apply differentiation to curve sketching and related optimisation problems

U34.AoS3.18

find derivatives of basic and more complicated functions and apply differentiation to curve sketching and optimisation problems

U34.AoS3.5

identification of local maximum/minimum values over an interval and application to solving optimisation problems in context, including identification of interval endpoint maximum and minimum values

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