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5.06 Equivalent expressions

Introduction

We have previously looked at  properties of operations with numeric  terms, and used  substitution  to evaluate algebraic expressions. We have also applied  distributive property  to express a sum of two whole numbers with a commn factor. Now we are going to use this knowledge to help us identify and create algebraic expressions that are equivalent.

Equivalent expressions by combining like terms

Equivalent expressions are expressions that have the same value or worth but do not look the same.

In the following expressions, we have been given the variable x to represent "an unknown number".

Expression 1Expression 2
3x+5x6x+2x

Although x represents an unknown number, it represents the same number anywhere it is used in an expression. So we can think of Expression 1 as 3 groups of x plus another 5 groups of x, or 8 groups of x altogether.

We can combine the two terms because they are "like terms", which means they have the same makeup of coefficients and variables. Sometimes we have terms that are not the same makeup, and we are not able to combine them. For example 3x + 5xy cannot be combined because they are not like terms. The term 5xy has the additional variable of y, which means 5 \times x \times y.

We can think of the Expression 2 as 6 groups of x plus another 2 groups of x. Again we can combine these to have 8 groups of x because they are like terms.

Now let's check if the two expressions are equivalent. To do this, we can substitute any value for x. Let's try replacing x with 7 in both expressions.

Expression 1:

\displaystyle 3x + 5x\displaystyle =\displaystyle 3\times 7+5\times 7Substitute the given value of 7 for x
\displaystyle =\displaystyle 21 + 35
\displaystyle =\displaystyle 56

Expression 2:

\displaystyle 6x + 2x\displaystyle =\displaystyle 6\times 7+2\times 7Substitute the given value of 7 for x
\displaystyle =\displaystyle 42 + 14
\displaystyle =\displaystyle 56

When 7 is substituted for x, both expressions have a value of 56. This confirms that the two expressions are equivalent.

Examples

Example 1

Choose all expressions that are equivalent to 7k.

A
5k-2k
B
6+k+6k-6
C
6k
D
7+k
E
2k+5k
Worked Solution
Create a strategy

Combine like terms for each expression and compare them to the original expression.

Apply the idea

Option A:

\displaystyle 5k-2k\displaystyle =\displaystyle 3kSimplify
\displaystyle \neq\displaystyle 7kCompare

Option B:

\displaystyle 6+k+6k-6\displaystyle =\displaystyle 7kCombine like terms

Option C:

6k \neq 7k

Option D:

7+k \neq 7k

Option E:

\displaystyle 2k+5k\displaystyle =\displaystyle 7kSimplify

Option B and Option E are equivalent expressions of 7k.

Example 2

Consider the following:

a

Select the expression that is equivalent to: 7s+2b-4s

A
3s-2b
B
11s+2b
C
3s+2b
D
3b+2w
Worked Solution
Create a strategy

Simplify the original expression to compare it to the options.

Apply the idea
\displaystyle 7s+2b-4s\displaystyle =\displaystyle 3s+2bCombine like terms

Option C is an equivalent expression of 7s+2b-4s.

b

Select the expression that is equivalent to: 21w+4b

A
14w+7w-4b
B
7w+7w+7w+4b
C
21w-8b
D
14w+7w+4b
Worked Solution
Create a strategy

Combine like terms for each expression and compare them to the original expression.

Apply the idea

Option A:

\displaystyle 14w+7w-4b\displaystyle =\displaystyle 21w-4bAdd like terms
\displaystyle \neq\displaystyle 21w+4bCompare

Option B:

\displaystyle 7w+7w+7w+4b\displaystyle =\displaystyle 21w+4bAdd like terms

Option C:

21w-8b \neq 21w+4b

Option D:

\displaystyle 14w+7w+4b\displaystyle =\displaystyle 21w+4bAdd like terms

Option B and Option D are equivalent expressions of 21w+4b.

Idea summary

To determine whether two expressions are equivalent we can simplify the expressions and compare the simplified versions.

Equivalent expressions using distributive property

Equivalent expressions can also be produced by applying the distributive property. If we were to think about 3(m+2), using the idea that multiplication relates to groups, we can say that 3(m+2) is 3 groups of (m+2). So we have, 3\times m and 3\times 2. This gives us 3m and 6.

\displaystyle 3(m+2)\displaystyle =\displaystyle 3m+6

Similarly, given an algebraic expression, we can use our knowledge of the distributive property and greatest common factor (GCF), to factor the expression.

To find an equivalent expression for 16x+24, use the GCF of 16 and 24, which is 8.

\displaystyle 16x+24\displaystyle =\displaystyle 8\times 2 + 8\times 316x is 8 groups of 2x and 24 is 8 groups of 3
\displaystyle 16x+24\displaystyle =\displaystyle 8(2x+3)Factor out the GCF of 8

Examples

Example 3

Use distributive property to write an equivalent expression for 10(m+4)

Worked Solution
Create a strategy

Multiply 10 with each number and variable inside the parentheses.

Apply the idea
\displaystyle 10(m+4)\displaystyle =\displaystyle 10\times m + 10\times 4Apply distributive property
\displaystyle 10(m+4)\displaystyle =\displaystyle 10m + 40Evaluate
Reflect and check

Check by factoring, 10m+40 has a GCF of 10.

10m+40 means 10 groups of m and 10 groups of 4.

Applying the distributive property:

10m+40=10(m+4)

Idea summary

We can also apply the distributive property and greatest common factor to find equivalent expressions.

Outcomes

6.EE.A.3

Apply the properties of operations to generate equivalent expressions.

6.EE.A.4

Identify when two expressions are equivalent (i.e., When the two expressions name the same number regardless of which value is substituted into them).

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