Previously, we learned how to find unit rates . Now let's use the concept of unit rates to solve real world problems.
Remember that rates are very similar to ratios in that we can use them to calculate how much one measurement changes based on the change in another.
For example, we know a sprinter can run at a speed of 10 m/s. A speed of 10 \text{ m/s} means that the sprinter runs 10 meters in 1 second.
Because we know the unit rate, we can figure out how far the sprinter can run in 15 seconds.
Set up equivalent ratios and let x be the unknown distance the sprinter can travel in 15 seconds.
\displaystyle \dfrac{10\text{ m}}{1\text{ s}} | \displaystyle = | \displaystyle \dfrac {x}{15\text{ s}} | Substitute the values of the distance and time in the equivalent ratios. |
\displaystyle \dfrac{10\text{ m}}{1\text{ s}} | \displaystyle = | \displaystyle \dfrac {x}{15\text{ s}} | Consider what factor we multiply by 1 to get 15 |
\displaystyle \dfrac{10 \text{ m}}{1 \text{ s}} \times \dfrac{15}{15} | \displaystyle = | \displaystyle \dfrac {x}{15\text{ s}} | Multiply the numerator denominator by the same factor |
\displaystyle \dfrac{150\text{ m}}{15 \text{ s}} | \displaystyle = | \displaystyle \dfrac {x}{15\text{ s}} | Evaluate |
\displaystyle x | \displaystyle = | \displaystyle 150 \text{ m} | The sprinter will run 150 meters in 15 seconds. |
Let's have a look at a few more examples.
Henry bikes 45 miles in 3 hours.
What is the speed of the bike in miles per hour?
If Henry travels at this constant rate, what distance will Henry travel in 2 hours?
Iain feels like buying some ice-cream for himself and his friends.
A box of 6 Cornettos costs \$7.20.
A box of 4 Paddle pops costs \$6.40.
How much does each Cornetto cost?
How much does each Paddle pop cost?
Which type of ice cream is the better buy?
We can calculate any of the three parts in the rate equation given any other two.
We can treat rates like ratios so that we can multiply or divide the top and bottom of the ratio in fraction form by a number that gives an equivalent ratio.