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4.05 Find the unit rate

Introduction

Now that we have been introduced to  ratios  and  ratio tables  , we are now ready to learn how to find a unit rate when given a statement or table.

Unit rates

A rate is a measure of how quickly one measurement changes with respect to another. A commonly used rate in our everyday lives is speed, which is measured in distance over time.

Rates are measured by combining two different units into a single compound unit. We can write these compound units using a slash ( / ) between the different units, so "meters per second" becomes "\text{m/s}".

This compound unit represents the division of one measurement by another to get a rate. When rates are expressed such that the quantity of the denominator is 1, such as 2 feet per 1 second or 5 miles per 1 hour, they are called unit rates. We usually shorten this by not writing the number '1', such as 2 feet per second or 5 miles per hour. When we're asked to determine a rate, we are most often being asked for the unit rate.

Consider an Olympic sprinter who runs 100 meters in 10 seconds. Let's represent that as a rate:

\text{Sprinter's speed}= 100 \text{ m}/ 10 \text{ s}

We want to know how fast he can run in a single second. We can find how far the sprinter runs in 1 second by dividing the 100 meters evenly between the 10 seconds.

\text{Sprinter's speed}=\dfrac{100}{10} \text{m/s}

This calculation tells us that the sprinter runs 10 meters in one second.

We can write this as a unit rate for the sprinter's speed in meters per second using the compound unit m/s to give us:\text{Sprinter's speed}=10\text{ m/s}

Whenever we can, simplify the fraction to get the unit rate. This is much nicer to work with as we can now say that speed is 10 meters per second, rather than 100 meters per 10 seconds.

We can simplify the fraction to get the unit rate.

Let's look at the following examples on how to find the unit rate.

Examples

Example 1

A tap fills up a 240-liter tub in 4 hours.

a

Which of the following is the compound unit for the rate of water flow?

Worked Solution
Create a strategy

The rate of water flow represents the number of liters that flows from the tap each hour.

Apply the idea

The unit is liters per hour, L/hr.

b

What is the rate of water flow of the tap in liters per hour?

Worked Solution
Create a strategy

We can find the rate of water flow in liters per hour by dividing the capacity of the tub in liters by the number of hours passed.

Apply the idea
\displaystyle \text{Rate}\displaystyle =\displaystyle \dfrac{240}{4}\text{ L/hr}
\displaystyle =\displaystyle 60\text{ L/hr}Evaluate the division.

Example 2

A car travels 320\text{ km} in 4 hours.

a

Complete the table of values.

Time taken (hours)421
Distance traveled (kilometers)320
Worked Solution
Create a strategy

Since the time is being divided by 2 each time, divide the distance traveled by 2 for each new distance in the table.

Apply the idea
\displaystyle \text{Distance at } 2 \text{ hours}\displaystyle =\displaystyle \dfrac{320}{2}Divide 320 by 2
\displaystyle =\displaystyle 160 \text{ km}Evaluate
\displaystyle \text{Distance at } 1 \text{ hour}\displaystyle =\displaystyle \dfrac{160}{2}Divide 160 by 2
\displaystyle =\displaystyle 80 \text{ km}Evaluate

This means that the tables of values is given by:

Time taken (hours)421
Distance traveled (kilometers)32016080
b

What is the speed of the car in kilometers per hour?

Worked Solution
Create a strategy

Use the table from part (a) to find what the distance was after 1 hour.

Apply the idea
\displaystyle \text{Speed}\displaystyle =\displaystyle \dfrac{80 \text{ km}}{1 \text{ hr}}Divide 80 km by 1 hr
\displaystyle =\displaystyle 80 \text{ km/hr}Evaluate
Idea summary

A rate is a measure of how quickly one measurement changes with respect to another.

When rates are expressed as a quantity with a denominator of 1, such as 2 feet per second or 5 miles per hour, they are called unit rates.

Outcomes

6.RP.A.2

Understand the concept of a unit rate a/b associated with a ratio a:b with b ≠ 0, and use rate language in the context of a ratio relationship. Expectations for unit rates in this grade are limited to non-complex fractions.

6.RP.A.3

Use ratio and rate reasoning to solve real-world and mathematical problems, e.g. By reasoning about tables of equivalent ratios, tape diagrams, double number line diagrams, or equations.

6.RP.A.3.B

Solve unit rate problems including those involving unit pricing and constant speed.

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