The height $h$h, in meters, reached by a ball thrown in the air after $t$t seconds is given by the equation $h=10t-t^2$h=10t−t2.
Fill in the following table of values for $h=10t-t^2$h=10t−t2.
$t$t | $1$1 | $2$2 | $3$3 | $4$4 | $5$5 | $6$6 | $7$7 | $8$8 | $9$9 | $10$10 |
$h$h | $\editable{}$ | $16$16 | $\editable{}$ | $24$24 | $\editable{}$ | $\editable{}$ | $\editable{}$ | $16$16 | $\editable{}$ | $0$0 |
Graph the relationship $h=10t-t^2$h=10t−t2.
Determine the height of the ball after $5.5$5.5 seconds have elapsed.
What is the maximum height reached by the ball?
The sum of two integers is $80$80.
A rectangle is to be constructed with $80$80 meters of wire. The rectangle will have an area of $A=40x-x^2$A=40x−x2, where $x$x is the length of one side of the rectangle.
A ball is thrown upwards from a height of $4$4 ft with an initial velocity of $44$44 ft/s. The height at time $t$t of the ball is given by the equation $h=-16t^2+44t+4$h=−16t2+44t+4.