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2.06 Addition with larger numbers

Lesson

Are you ready?

Breaking up numbers into parts, often by place value, can help with addition. Do you know how to partition a number by place value?

Complete in the number expander for $18522$18522.

  1. $18522$18522 $=$= $\editable{}$ ten thousands $\editable{}$ thousands $\editable{}$ hundreds $2$2 tens $2$2 ones
  2. Write $18522$18522 as a number sentence.
    $\editable{}+\editable{}+\editable{}+20+2$+++20+2

Vocabulary:
  • Another word that we can use to describe the ones place is 'units'.

  • You might notice that sometimes the standard algorithm is called the 'vertical algorithm'. Let's think about why. When we use the standard algorithm, we line our numbers up in 'vertical' place value columns.

Learn 

We can use standard algorithms to work with larger numbers, as we do in this video.

Apply

Question 1

Let’s find the value of $6005+3005$6005+3005, by partitioning the numbers.

  1. Fill in the box with the missing number.

    $6005=6000+\editable{}$6005=6000+

  2. Fill in the box with the missing number.

    $3005=\editable{}+5$3005=+5

  3. Find the value of $6005+3005$6005+3005.

Question 2

Find the value of $91921+93700$91921+93700.

Remember!

We often call on different methods when we solve addition problems, so remember to use things such as:

  • bridge (build) to $10$10
  • partitioning numbers
  • number lines
  • place value
  • standard algorithms

Can you think of any other addition strategies that are useful?

 

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