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iGCSE (2021 Edition)

13.11 Graphs of linear equations

Lesson

We will now look at how to sketch a line directly from its equation, without needing to create a table of values first.

We have learnt that all linear relationships can be expressed in the form: $y=mx+c$y=mx+c, where $m$m is equal to the change in the $y$y-values for every increase in the $x$x-value by $1$1, and $c$c is the value of $y$y when $x=0$x=0.

Intercepts

Lines drawn on the number plane, extend forever in both directions.  If we ignore the special case of horizontal and vertical lines (which we will look at in another lesson), all other lines will either cross both the $x$x-axis and the $y$y-axis or they will pass through the origin, $\left(0,0\right)$(0,0).

Here are some examples:

We use the word intercept to refer to the point where the line crosses or intercepts with an axis.

Intercepts
  • The $x$x-intercept is the point where the line crosses the $x$x-axis. The coordinates of the $x$x-intercept will always have a $y$y-coordinate of zero.
  • The $y$y-intercept is the point where the line crosses the $y$y-axis. The coordinates of the $y$y-intercept will always have an $x$x-coordinate of zero.

Note: Every straight line must have at least one intercept but cannot have any more than two intercepts.

As mentioned previously, we only need to identify two points to sketch a a straight line, and the $x$x and $y$y-intercepts are probably the most useful points to identify and plot. They are also two of the easier points to find as we are substituting in either the values $x=0$x=0 or $y=0$y=0, which simplifies the work needed to solve. 

The $y$y-intercept can be thought of as either the co-ordinate the point where the $y$y-axis is crossed, or simply the $y$y-value at this point (as the $x$x-value is by default $0$0).

 

Worked example

EXAMPLE 1

Find the $y$y-intercept for the straight line below:

The $y$y-intercept is $-6$6, and the coordinates of the $y$y-intercept are $\left(0,-6\right)$(0,6).

 

Practice Question

question 1

Consider the following graph.

 

Loading Graph...
A coordinate plane with the following attributes:

Axis intersection at centre

Tick label format is fraction

The x major unit is $1$1

The x axis ends at $7$7

The x axis starts from $-7$7

The x minor unit is $1$1

The y major unit is $1$1

The y axis ends at $7$7

The y axis starts from $-7$7

The y minor unit is $1$1

The following elements are present:

Function: 4 - (4*x)/3

 

  1. State the $x$x-value of the $x$x-intercept.

  2. State the $y$y-value of the $y$y-intercept.

question 2

Consider the linear equation $y=2x-4$y=2x4.

  1. What are the coordinates of the $y$y-intercept?

    Give your answer in the form $\left(a,b\right)$(a,b).

  2. What are the coordinates of the $x$x-intercept?

    Give your answer in the form $\left(a,b\right)$(a,b).

  3. Now, sketch the line $y=2x-4$y=2x4:

    Loading Graph...

 

The gradient of a line

The change in $y$y-values for every increase in the $x$x-value is called the gradient. The gradient is often thought of as the 'slope' of the line- how steep it is. 

The gradient

The value of the gradient, $m$m, relates to the line $y=mx+c$y=mx+cas follows:

  • A negative gradient ($m<0$m<0) means the line is decreasing
  • A positive gradient ($m>0$m>0) means the line is increasing
  • A zero gradient ($m=0$m=0) means the line is horizontal
  • The higher the value of $m$m, the steeper the line.

 

Practice Question

question 3

What is the gradient $m$m of the line $y=9x+3$y=9x+3?

 

Gradient-intercept form of a straight line

Any straight line on the coordinate plane is defined entirely by its gradient and its $y$y-intercept. 

We can represent the equation of any straight line, except vertical lines, using what is known as the gradient-intercept form of a straight line.

Gradient-intercept form of a straight line

All linear relationships can be expressed in the form: $y=mx+c$y=mx+c.

  • $m$m is equal to the gradient, or slope, of the line.
  • $c$c is the value of the $y$y-intercept.

We can use the applet below to see the effect of varying $m$m and $c$c on both the line and its equation.

 

Coefficients and constant terms

In algebra, any number written immediately in front of a variable, is called a coefficient. For example, in the term $3x$3x, the coefficient of $x$x is $3$3. Any number by itself is known as a constant term.

In the gradient-intercept form of a line, $y=mx+c$y=mx+c, the gradient, $m$m, is the coefficient of $x$x, and the $y$y-intercept, $c$c, is a constant term.

Practice Questions

question 4

Consider the line graph shown below:

Loading Graph...

  1. The $x$x-value at the $y$y-intercept is $0$0.
    What is the $y$y-value at this point?

  2. The equation of the line is $y=-2x+3$y=2x+3.

    This is of the form $y=mx+c$y=mx+c.

    Which pronumeral represents the $y$y-intercept?

    $y$y

    A

    $m$m

    B

    $x$x

    C

    $c$c

    D

Question 5

Consider the linear equation $y=2x+9$y=2x+9.

What are the values of the gradient $m$m and the $y$y-intercept $c$c?

  1. $m$m $=$= $\editable{}$

    $c$c $=$= $\editable{}$

 

 

Approximate solutions of equations

You can solve linear equations approximately by looking at the graph of the line.

Worked example

example 2

Estimate the solution to the equation $-\frac{2}{3}x+\frac{5}{3}=0$23x+53=0 by graphing the line $y=-\frac{2}{3}x+\frac{5}{3}$y=23x+53.

The graph of the line is shown below:

To solve the equation $-\frac{2}{3}x+\frac{5}{3}=0$23x+53=0 we need to find the $x$x-coordinate of the $x$x-intercept. By looking at the $x$x-intercept on the graph we can approximate this to be: $x\approx2.5$x2.5.

Outcomes

0580C2.11A

Construct tables of values for functions of the form ax + b, where a and b are integer constants. Draw and interpret these graphs. Solve linear equations approximately, including finding and interpreting roots by graphical methods. Recognise, sketch and interpret graphs of functions

0580C3.2

Find the gradient of a straight line.

0580C3.4

Interpret and obtain the equation of a straight line graph in the form y = mx + c.

0580E3.2

Find the gradient of a straight line. Calculate the gradient of a straight line from the coordinates of two points on it.

0580E3.4

Interpret and obtain the equation of a straight line graph.

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