Since $\sqrt{32}$√32 and $\sqrt{2}$√2 are not like radicals, $\sqrt{32}+\sqrt{2}$√32+√2 cannot be simplified. True or false?
True
False
Evaluate to one decimal place.
True or False?
$5-\sqrt{5}=\sqrt{5}$5−√5=√5
Simplify: $10\sqrt{2}+14\sqrt{2}$10√2+14√2