A table of values, created using an equation, forms a set of points that can be plotted on a number plane. A line, drawn through the points, becomes the graph of the equation.
We'll begin by creating a table of values for the following equation:
$y=3x-5$y=3x−5
The first row of the table will contain values for the independent variable (in this case, $x$x). The choice of $x$x-value is often determined by the context, but in many cases they will be given. To find the corresponding $y$y-value, we substitute each $x$x-value into the equation $y=3x-5$y=3x−5.
$x$x | $1$1 | $2$2 | $3$3 | $4$4 |
---|---|---|---|---|
$y$y |
Substituting $x=1$x=1:
$y$y | $=$= | $3\times1-5$3×1−5 |
$=$= | $3-5$3−5 | |
$=$= | $-2$−2 |
Substituting the remaining values of $x$x, allows us to complete the table:
$x$x | $1$1 | $2$2 | $3$3 | $4$4 |
---|---|---|---|---|
$y$y | $-2$−2 | $1$1 | $4$4 | $7$7 |
The $x$x and $y$y value in each column of the table can be grouped together to form the coordinates of a single point, $\left(x,y\right)$(x,y).
Each point can then be plotted on a $xy$xy-plane.
To plot a point, $\left(a,b\right)$(a,b), on a number plane, we first identify where $x=a$x=a lies along the $x$x-axis, and where $y=b$y=b lies along the $y$y axis.
For example, to plot the point $\left(3,4\right)$(3,4), we identify $x=3$x=3 on the $x$x-axis and construct a vertical line through this point. Then we identify $y=4$y=4 on the $y$y-axis and construct a horizontal line through this point. The point where the two lines meet has the coordinates $\left(3,4\right)$(3,4).
If we sketch a straight line through the points, we get the graph of $y=3x-5$y=3x−5.
Notice that when sketching a straight line through a set of points, the line should not start and end at the points, but continue beyond them, across the entire coordinate plane.
To sketch a straight line graph we actually only need to identify two points!
The word intercept in mathematics refers to a point where a line or curve crosses or intersects with the axes.
Consider what happens as a point moves up or down along the $y$y-axis. It will eventually reach the origin $\left(0,0\right)$(0,0) where $y=0$y=0. Now, if the point moves along the $x$x-axis in either direction, the $y$y-value is still $0$0.
Similarly, consider what happens as a point moves along the $x$x-axis. It will eventually reach the origin where $x=0$x=0. Now, if the point moves along the $y$y-axis in either direction, the $x$x-value is still $0$0.
This interactive demonstrates the idea behind the coordinates of $x$x and $y$y-intercepts.
The $x$x-intercept occurs at the point where $y=0$y=0.
The $y$y-intercept occurs at the point where $x=0$x=0.
$x$x-intercepts occur when the $y$y-value is $0$0. So let $y=0$y=0 and then solve for $x$x.
$y$y-intercepts occur when the $x$x-value is $0$0. So let $x=0$x=0 and then solve for $y$y.
Alternatively we can read the $y$y-intercept value from the equation when it is in the form $y=mx+c$y=mx+c. The value of $c$c is the value of the $y$y-intercept.
We can also graph a line by identifying the gradient and the $y$y-intercept from the equation when it is in the form $y=mx+c$y=mx+c.
We know that the $y$y-intercept occurs at $\left(0,c\right)$(0,c), and the gradient is equal to $m$m. Using this information we can plot the point at the $y$y-intercept (or any other point by substituting in a value for $x$x and solving for $y$y) and then move right by $1$1, and up (or down if $m$m is negative) by $m$m.
As as an example, if we have the equation $y=2x+3$y=2x+3, then we know the $y$y-intercept is at $\left(0,3\right)$(0,3) and as the gradient is $2$2, another point will be at $\left(1,3+2\right)=\left(1,5\right)$(1,3+2)=(1,5).
Consider the equation $y=2x-4$y=2x−4.
Complete the table of values.
$x$x | $0$0 | $1$1 | $2$2 | $3$3 |
---|---|---|---|---|
$y$y | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
Using the table of values, plot the points that correspond to when $x=0$x=0 and $y=0$y=0:
Using the points plotted above, sketch the line that passes through the two points:
Consider the linear equation $y=2x-2$y=2x−2.
What are the coordinates of the $y$y-intercept?
Give your answer in the form $\left(a,b\right)$(a,b).
What are the coordinates of the $x$x-intercept?
Give your answer in the form $\left(a,b\right)$(a,b).
Now, sketch the line $y=2x-2$y=2x−2:
Sketch the line $y=-x-5$y=−x−5 using the $y$y-intercept and any other point on the line.
Sketch the line that has a gradient of $-3$−3 and an $x$x-intercept of $-5$−5.
The line with equation given by $x=a$x=a, with $a$a as any real number, is drawn parallel to the $y$y axis passing through the point $\left(a,0\right)$(a,0) on the $x$x axis. Three examples, specifically $x=-1$x=−1, $x=1$x=1, and $x=2\sqrt{2}$x=2√2 are shown in the diagram below:
A nice way to think about the line given by the equation $x=a$x=a is to realise that every point on it has the $x$x part of the coordinate address equal to $a$a, and the $y$y part can be any number. Thus points like $\left(a,-3\right),\left(a,0\right),\left(a,5\right),\left(a,23\right)$(a,−3),(a,0),(a,5),(a,23) are all on the line, one directly above the other. Hence, the line is perpendicular to the $x$x-axis.
In a similar way, the line with equation $y=b$y=b, where $b$b is a constant, is parallel to the $x$x-axis and passes through the point $\left(0,b\right)$(0,b) on the $y$y-axis. The lines $y=-3,y=2$y=−3,y=2 and $y=5$y=5 are shown in the following diagram:
Plot the line $x=-8$x=−8 on the number plane.
Find the intersection of the lines $x=6$x=6 and the line $y=-3$y=−3 .