Consider the inequality $x^2-3x-10\ge0$x2−3x−10≥0.
First factor $x^2-3x-10$x2−3x−10.
For what values of $x$x is $x^2-3x-10=0$x2−3x−10=0? Leave your solutions on the same line separated by a comma.
To solve the inequality, Micky splits up the entire number line into three intervals, and tests a value from each interval to see if it satisfies the inequality $x^2-3x-10\ge0$x2−3x−10≥0.
Interval A ($x<-2$x<−2) | $x=-2$x=−2 |
Interval B ($-2 |
$x=5$x=5 | Interval C ($x>5$x>5) |
Value to test | Value to test | Value to test | ||
$x=-3$x=−3 | $x=1$x=1 | $x=7$x=7 |
Which values of $x$x satisfy the inequality $x^2-3x-10\ge0$x2−3x−10≥0? Select all that apply.
$x=7$x=7
$x=-3$x=−3
$x=1$x=1
Hence, state the solution to the inequality $x^2-3x-10\ge0$x2−3x−10≥0. You may use the keywords "and"/"or".
Consider the inequality $x^2-9\le0$x2−9≤0.
Consider the inequality $x^2-x-20<0$x2−x−20<0.
Consider the inequality $-x^2+x+20\le0$−x2+x+20≤0.