Interactive practice questions
The position (in metres) of an object along a straight line after $t$t seconds is modelled by $x\left(t\right)=6t^2$x(t)=6t2.
State the velocity $v\left(t\right)$v(t) of the particle at time $t$t.
Which of the following represent the velocity of the particle after $4$4 seconds? Select all that apply.
$x'\left(4\right)$x′(4)
$v'\left(4\right)$v′(4)
$x\left(4\right)$x(4)
$v\left(4\right)$v(4)
Hence find the velocity of the particle after $4$4 seconds.
The position (in metres) of an object along a straight line after $t$t seconds is modelled by $x\left(t\right)=3t^3-4t^2$x(t)=3t3−4t2.
Let $s=10+12t-4.7t^2$s=10+12t−4.7t2 be the height of an object in metres at time $t$t in seconds.
A car starts at rest and has a displacement of $s$s metres in $t$t seconds, where $s=\frac{1}{6}t^3+\frac{1}{4}t^2$s=16t3+14t2.