A parabola of the form $y=ax^2$y=ax2 goes through the point $\left(2,-4\right)$(2,−4).
What is the value of $a$a?
What are the coordinates of the vertex?
Vertex $=$=$\left(\editable{},\editable{}\right)$(,)
Plot the graph of the parabola.
Consider the graph.
A parabola has its turning point at $x=-3$x=−3 and one of the $x$x-intercepts is $x=1$x=1.
Write down the equation of the parabola that has the same shape as $f\left(x\right)=6x^2$f(x)=6x2, and vertex at $\left(-2,3\right)$(−2,3):