A cylinder has three faces: two identical circular bases and a curved surface that joins the two bases together.
The surface area of a cylinder is the sum of the areas of these three faces. We already know how to find the area of the circular bases, but what about the curved surface?
By "unwrapping" the cylinder we can treat the curved surface as a rectangle, with one side length equal to the height of the cylinder, and the other the perimeter (circumference) of the base circle. This is given by 2\pi r, where r is the radius.
This means the surface area of the curved part of a cylinder is 2\pi rh, where r is the radius and h is the height.
We can see how the cylinder unrolls to make this rectangle in the applet below:
The length of the rectangle that wraps around the cylinder is equal to the circumference of the face of the cylinder.
To find the surface area of the whole cylinder, we need to add the area of the top and bottom circles to the area of the curved part. Both of these circles have an area of \pi r^{2}, so the surface area of a cylinder is: \text{Surface area of a cylinder}=2\pi r^{2}+2\pi rh, where r is the radius and h is the height of the cylinder.
Consider the following cylinder.
Find the curved surface area of the cylinder to two decimal places.
Consider the cylinder shown in the diagram below.
Find the surface area of the cylinder in square centimetres. Round your answer to one decimal place.
Use your answer from part (a) to find the surface area of the cylinder in square millimetres.
The area of the circular face on a cylinder is 8281 \pi\text{ m}^2. The total surface area of the cylinder is 25\,662 \pi\text{ m}^2.
If the radius of the cylinder is r\text{ m}, find the value of r.
Find the height h of the cylinder.