We've seen equations like $y=B^x$y=Bx before. It's straightforward enough to find $y$y when we know $x$x, but is it possible to find $x$x if we know $y$y?
The expression $B^x$Bx, if $x$x is a natural number, means the number of $B$B factors multiplied together is $x$x. So to find $x$x in $3^x=81$3x=81 we ask how many $3$3 factors are in $81$81, and the answer is $4$4. But we saw from exponential graphs that $x$x can in general be any real number, including irrational numbers. In that case it doesn't make sense to multiply $B$B $x$x times.
Logarithms are expressions of the form $\log_By$logBy, where $B$B is some number and $y$y is a pronumeral. $B$B is called the base of the logarithm. The definition of a logarithm is that if
In other words, $\log_By$logBy is the number of $B$B factors that multiply together to make $y$y. It follows that $\log_381=4$log381=4.
Of course, the value of the logarithm could be any real number. We will soon see how to find the exact values of logarithms, but we can approximate the value using a calculator.
First note that by convention, if $B$B is not specified that means a base of $10$10. So $\log y=\log_10y$logy=log10y. If we wanted to find $\log81$log81, then we can press the "log" button on a calculator and then enter $81$81. This gives us $1.908$1.908 to three decimal places.
Logarithms are expressions of the form $\log_By$logBy, where $B$B is any number and $y$y is a pronumeral.
In $\log_By$logBy, $B$B is the base of the logarithm.
By convention, if the base is not specified then $B=10$B=10.
If $y=B^x$y=Bx then $\log_By=x$logBy=x, so $y$y is the number of $B$B factors that are multiplied together to give $x$x.
Rewrite the equation $9^x=81$9x=81 in logarithmic form (with the index as the subject of the equation).
Round your answer to two decimal places.
Use the definition of a logarithm to establish and apply the laws of logarithms and investigate logarithmic scales in measurement