An investment with compound interest differs from one with simple interest in the way that it always calculates interest based on the current total amount. In other words, any interest that is earned will be taken into account for the next time interest is calculated.
Since compound interest always calculates the interest based on the current total, we can think of it as a continuous application of simple interest, one period at a time, where we update the principal amount to match the new total after each application.
We can calculate compound interest in this way using a table like the one below. In this example, the starting principal amount is \$1000 with a compounding interest rate of 5\% per annum.
Year | Principal used | Compound interest earned | New total |
---|---|---|---|
1 | \$1000 | \$50 | \$1050 |
2 | \$1050 | \$52.50 | \$1102.50 |
3 | \$1102.50 | \$55.13 | \$1157.63 |
If we check, we will see that the new total at the end of a year is always equal to 1.05 times the principal amount used, which was equal to the total at the end of the previous year.
With each earning of interest the total increases, increasing the principal amount used which in turn increases the amount of interest earned each year. What this tells us is that compound interest results in a total that increases at an increasing rate.
When calculating compound interest using repeated applications of simple interest, we notice that the new total at the end of each year is simply a percentage increase of the previous year's total.
Using the example with \$1000 invested at an interest rate of 5\% p.a., compounding annually, our calculations take the form:
\text{End of 1st year} = 1000 \times 1.05
\text{End of 2nd year} = 1000 \times 1.05 \times 1.05
\text{End of 3rd year} = 1000 \times 1.05 \times 1.05 \times 1.05
If we don't evaluate each year's total, we can see a pattern form. Since each percentage increase will be the same, we can just apply it as many times as there are periods of interest.
It is also worth noting that since we are multiplying by the same amount for each percentage increase when calculating compound interest, we could also compress these terms using indices, like so:
\text{End of 1st year} = 1000 \times 1.05
\text{End of 2nd year} = 1000 \times {1.05}^2
\text{End of 3rd year} = 1000 \times {1.05}^3
\$3200 is invested for three years at a rate of 6\% p.a., compounding annually.
Complete the table row for the third year.
Balance + interest | Total balance | Interest earned | |
---|---|---|---|
First year | - | \$3200 | \$192 |
Second year | \$3200 + \$192 | \$3392 | \$203.52 |
Third year | \$3392 + \$ \,⬚ | \$\,⬚ | \$ \, ⬚ |
Fourth year | \$\, ⬚ | \$ \, ⬚ | - |
Complete the table row for the Fourth Year, to determine the final value of the investment.
Calculate the total interest earned over the three years.
Bill invests \$15\,000 at an interest rate of 2.8 \% p.a., compounding annually. After how many years will Bill's investment be greater than \$17\,500?
We can use repeated applications of simple interest to find the compound interest of an investment or loan.
Appreciation is when an item's value increases over time, usually by some fixed percentage of its current value. An example of this is how antiques or collectables become rarer and more expensive over time.
Depreciation is when an item's value decreases over time, again by some fixed percentage of its current value. An example of this is how a new car will lose value over time as it gets older and more out of date.
Since we often calculate appreciation and depreciation in terms of annual percentage increases or decreases, we can model their change in value the same way that we do with compound interest.
Looking at it one year at a time, appreciation is simply a repeated application of percentage increases, exactly like compound interest.
A new book depreciates in value by \dfrac{33}{5} \, \% every month. The book is currently valued at \$60.
How much will the book be valued at in one month's time?
How much will the book be valued at in two months' time?
Which of the following expressions can be used to calculate the value of the book in 4 months' time? Select all that apply.
Using either of the expressions found in the previous part, calculate the value of the book in 4 months' time.
Appreciation is when an item's value increases over time, usually by a fixed percentage. Appreciation requires repeated applications of percentage increase.
Depreciation is when an item's value decreases over time, usually by a fixed percentage. Depreciation requires repeated applications of percentage decrease.
So far, the examples we have looked at have all had interest calculated annually. However, interest can be calculated over any period and the interest rate per period will need to match it.
To match the interest rate to the period duration, we can use interest rate conversions.
It is also important to match the total number of periods to the duration of the investment. To do this, we can simply divide the duration of the investment by the duration of the period.
Victoria borrows \$35\,000 at a rate of 4.8\% p.a, compounding monthly.
After 4 months, Victoria repays the loan all at once. How much money does she pay back in total?
How much interest was generated on the loan over the four months?
To match the interest rate to the period duration, we can use interest rate conversions.
Compounded rate | Divide annual rate by |
---|---|
\text{Daily} | 365 |
\text{Weekly} | 52 |
\text{Monthly} | 12 |
\text{Quarterly} | 4 |
\text{Half-yealy} | 2 |