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10&10a

1.08 Factorising monic quadratic trinomials

Lesson

Factorise monic quadratic trinomials

We call expressions of the form x^2+mx+n, where x is a pronumeral and m and n are numbers, monic quadratic trinomials. In order to factorise these, we want to use the rule AC+AD+BC+BD=\left(A+B\right)\left(C+D\right), but there are three terms instead of four.

The first term is x^2. Since x is a pronumeral, we can't really split it up, so to fit the distributive law we want A=x and C=x.

If we also let B=p and D=q, then we get \left(x+p\right)\left(x+q\right)=x^2+px+qx+pq by expansion. We can then factorise x from the two middle terms to get x^2+\left(p+q\right)x+pq.

Comparing this to the monic quadratic expression we have x^2+mx+n=x^2+\left(p+q\right)x+pq. Equating the coefficients of x tells us m=p+q and n=pq. This means that there are two numbers, p and q which add to give m and multiply to give n. If we can find these two numbers we can factorise the monic quadratic expression.

Examples

Example 1

Factorise: x^2+6x+8

Worked Solution
Create a strategy

Find two numbers p and q that add to 6 and multiply to 8, then factorise using \left(x+p\right)\left(x+q\right).

Apply the idea

Notice that 6 and 8 are positive, then both p and q must be positive. We need factors of 8 have add to 6, which are 2 and 4.

\displaystyle x^2+6x+8\displaystyle =\displaystyle (x+2 )(x+4)Factorise

Example 2

Factorise: x^2-12x+36

Worked Solution
Create a strategy

Use the rule for perfect square expansion: A^2-2AB+B^2=\left(A-B\right)^2.

Apply the idea

There are two square terms, x^2 and 36=6^2. This means A=x and B=6. We know this works because 2AB=2\times 6\times x=12x.

\displaystyle x^2-12x+36\displaystyle =\displaystyle \left(x-6\right)^2Use the rule

Example 3

Factorise: x^2-17x+60

Worked Solution
Create a strategy

Find two numbers that add to -17 and multiply to give 60, then factorise.

Apply the idea

We need to choose factors of 60 that have sum of -17. The factors are -5 and -12.

\displaystyle x^2-17x+60\displaystyle =\displaystyle \left(x-5\right)\left(x-12\right)Factorise
Idea summary

An expression of the form x^2+mx+n is a monic quadratic trinomial.

To factorise expressions like this, we find a pair of numbers p and q such that p+q=m and pq=n.

Then the factorisation is x^2+mx+n=\left(x+p\right)\left(x+q\right).

Outcomes

ACMNA230

Factorise algebraic expressions by taking out a common algebraic factor

ACMNA231

Simplify algebraic products and quotients using index laws

ACMNA232

Apply the four operations to simple algebraic fractions with numerical denominators

ACMNA233

Expand binomial products and factorise monic quadratic expressions using a variety of strategies

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