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Year 10

3.01 Quadratic equations

Lesson

Quadratic equations

We call equations like x-7=2 linear equations. These are equations where the variable of interest has a power of 1. Linear equations have only one solution. That is, there is only one value of the variable which will make the equation true. In this case, the only solution is x=9.

If instead, the variable of interest in the equation has a power of 2, we call them quadratic equations. Quadratic equations can potentially have two solutions. For example, in the equation x^{2}-7=2, there are two solutions, x=3 and x=-3. We can also write this as x= \pm 3.

The symbol \pm means "plus or minus". We can use this as a shorthand for both the positive and negative of a number. We can check these solutions by substituting them into the original equation and seeing if it holds true.

Examples

Example 1

Solve \dfrac{x^{2}}{16}-3=6 for x.

Worked Solution
Create a strategy

We need to use inverse operations and then reverse the square operation.

Apply the idea
\displaystyle \dfrac{x^{2}}{16}-3\displaystyle =\displaystyle 6Write the equation
\displaystyle \dfrac{x^{2}}{16}\displaystyle =\displaystyle 9Add 3 to both sides
\displaystyle x^{2}\displaystyle =\displaystyle 144Multiply both sides by 16
\displaystyle x\displaystyle =\displaystyle \pm 12Square root both sides
Idea summary

Equations where the variable of interest has a highest power of one are linear equations. These have at most one solution.

Equations where the variable of interest has a highest power of two are quadratic equations. These have at most two solutions.

The symbol \pm means "plus or minus".

If we can rearrange a quadratic equation into the form x^{2}=k, then we can solve the equation by taking the positive and negative square roots. That is, x=\pm\sqrt{k}.

The null factor law

The null factor law states that if a product of two or more factors is equal to 0, then at least one of those factors must be equal to 0. For example, if xy=0 then either x=0 or y=0. We can use this to solve quadratic equations.

If we can rearrange a quadratic equation into the form (x-a)(x-b)=0 then we know that either x-a=0 or x-b=0. We can solve the quadratic equation by solving each of these linear equations.

Examples

Example 2

Solve (x-6)(x+7)=0 for x.

Worked Solution
Create a strategy

Equate both factors to zero and solve.

Apply the idea
\displaystyle x-6\displaystyle =\displaystyle 0Equate the first factor to 0
\displaystyle x\displaystyle =\displaystyle 0+6Add 6 to both sides
\displaystyle =\displaystyle 6Evaluate
\displaystyle x+7\displaystyle =\displaystyle 0Equate the second factor to 0
\displaystyle x\displaystyle =\displaystyle 0-7Subtract 7 from both sides
\displaystyle =\displaystyle -7Evaluate
Idea summary

The null factor law states that if a product of two or more factors is equal to 0, then at least one of those factors must be equal to 0.

If we can rearrange a quadratic equation into the form (x-a)(x-b)=0 then we know that either x-a=0 or x-b=0. We can solve the quadratic equation by solving each of these linear equations.

Outcomes

ACMNA230

Factorise algebraic expressions by taking out a common algebraic factor

ACMNA231

Simplify algebraic products and quotients using index laws

ACMNA232

Apply the four operations to simple algebraic fractions with numerical denominators

ACMNA233

Expand binomial products and factorise monic quadratic expressions using a variety of strategies

ACMNA241

Solve simple quadratic equations using a range of strategies

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