# 4.02 Perimeter

Lesson

The word "perimeter" comes from the Greek word perimetron. Peri - meaning around and metron - meaning measure. It has the following definition:

Perimeter

The distance around the external boundary of a two-dimensional shape.

A perimeter can be calculated by adding together the lengths of all the sides of the shape.

### Calculating perimeters

Consider the scalene triangle below. To find its perimeter we add up the three side lengths. Notice that all sides are measured using the same units.

 Perimeter $=$= $14+12+6$14+12+6 cm $=$= $32$32 cm

We can get clever with the way that we carry out calculations if the shape we are looking at has side lengths that are equal.

Here is a rectangle. We know that rectangles have opposite sides of equal length.

 Perimeter $=$= $2\times13+2\times6$2×13+2×6 (we have two $13$13 mm sides and two $6$6 mm sides.) $=$= $26+12$26+12 mm $=$= $38$38 mm

A square has $4$4 sides of the same length, so the perimeter of a square will be $4\times\text{side length}$4×side length.

 Perimeter $=$= $4\times7.4$4×7.4 cm $=$= $29.6$29.6 cm

Remember!

To find the perimeter of a shape, add up all the side lengths.

For finding the perimeter of a rectangle and a square we can use the following formulas:

• Perimeter of a Rectangle$=$=$2\times\left(\text{length}+\text{width}\right)$2×(length+width), which is often abbreviated to the formula $P=2L+2W$P=2L+2W
• Perimeter of a Square$=$=$4\times\text{side length}$4×side length, which can be written as $P=4s$P=4s

### Other shapes

All perimeters can be found by adding up each side length one at a time as we travel around the shape.

Here is a trapezium. To find its perimeter we add up the side lengths.

 Perimeter $=$= $1.2+1.3+2.4+1.8$1.2+1.3+2.4+1.8 m $=$= $6.7$6.7 m

Also keep in mind that we can construct simple rules for other shapes as necessary, such as grouping together sides of the same lengths. For instance, let's calculate the perimeter of the figure below:

 Perimeter $=$= $3\times1+2\times3.6+1.4+1.5+3.44$3×1+2×3.6+1.4+1.5+3.44 m $=$= $3+7.2+2.9+3.44$3+7.2+2.9+3.44 m $=$= $16.54$16.54 m

#### Worked example

##### Example 1

Find the perimeter of the shape pictured below, where the measurements are in metres:

Think: At first glance it might look like we don't have enough information to add up all the sides. If we think carefully, however, notice that the two unknown horizontal side lengths must add up to $13$13 m. Similarly, the two unknown vertical side lengths must add up to $8$8 m. We can picture this by moving the sides to the edge as follows:

This shape is a rectangle with exactly the same perimeter as our original shape (although a different area).

Do: So the perimeter of the composite shape can be calculated as:

 Perimeter $=$= $2\times\left(8+13\right)$2×(8+13) m $=$= $2\times21$2×21 m $=$= $42$42 m

#### Practice questions

##### Question 1

Find the perimeter of a rectangle with a length of $4$4 m, and a width of $23$23 m.

##### Question 2

Find the perimeter of the isosceles triangle shown.

##### Question 3

Consider the following figure.

1. Find the length $x$x.

2. Find the length $y$y.

3. Calculate the perimeter of the figure.

### Finding an unknown side

Given the perimeter of our shape, we can often work out how long any missing sides are by using the special features of that shape together with any other given measurements.

#### Worked examples

##### Example 2

A $32$32 cm long piece of wire is bent into the shape of a square. What is the side length of the square?

Think: Since the piece of wire was $32$32 cm long, we know that the perimeter of the square will be $32$32 cm. We can reverse the formula for the perimeter of a square, $\text{Perimeter}=4\times\text{side length}$Perimeter=4×side length, to find a solution.

Do: Draw a diagram then

 $P$P $=$= $4\times\text{side length}$4×side length Write out the formula. $32$32 $=$= $4\times\text{side length}$4×side length Substitute in the known value. $32$32 $=$= $4\times8$4×8 Think $4$4 times $8$8 is $32$32. $\therefore s$∴s $=$= $8$8

So we find that the side length of the square is $8$8 cm.

##### Example 3

A rectangle has length $8$8 cm and perimeter $26$26 cm. Find the width of the rectangle.

Think: We can try reversing the formula for the perimeter of a rectangle, $P=2L+2W$P=2L+2W, to find a solution.

Do: Draw a diagram then

 $P$P $=$= $2L+2W$2L+2W Write out the formula. $26$26 $=$= $2\times8+2W$2×8+2W Substitute in the known values. $26$26 $=$= $16+2W$16+2W Think $16+10=26$16+10=26 therefore $2W$2W $=$= $10$10 $W$W $=$= $5$5 because $2\times5=10$2×5=10

So we find that the width of the rectangle is $5$5 cm.

#### Practice questions

##### Question 4

Find the side length $d$d indicated on the diagram. The perimeter of the shape is $35$35 cm.

##### Question 5

A rectangle has a perimeter of $42$42 cm. If its width is $7$7 cm, what is its length?

### In context

Finding the boundary length of a shape lends itself to many practical applications such as pricing fencing to boarder a property or pool, finding length of skirting boards to surround a room, distance in a training circuit around the neighbourhood and so forth.

#### Worked example

##### Example 4

Andrea needs to buy fencing to keep he dog from digging up her vegetable garden. She has a rectangular garden bed that is $3$3 metres wide and $4$4 metres long and requires new fencing on all sides. If the fencing costs $\$25$$25 m, how much in total will the fencing cost? Think: First find the length of fencing and then multiply by the cost. Do: Draw a diagram then  Length of fence == 2\left(L+W\right)2(L+W) == 2\left(3+4\right)2(3+4) m == 1414 m Thus the cost is:  Cost of fencing == 14\times2514×25 == \350$$350

#### Practice questions

##### Question 6

A rectangular athletics field is $140$140 metres long and $40$40 metres wide. How far, in km, will an athlete run by completing $6$6 laps of along the edge of the field?

##### Question 7

Find the length of wire needed to create the frame of this rectangular prism.

##### Question 8

A swimming pool has a $3$3 m wide path around its edge. The outer width of the path is $15$15 m and the length is $29$29 m, as shown in the figure.

1. What are the dimensions of the pool without the path around it?

Length $=$=$\editable{}$ m

Width $=$=$\editable{}$ m

2. What is the perimeter of the pool?

### Outcomes

#### 1.3.1

choose and use appropriate metric units of length, their abbreviations, conversions between them, and appropriate levels of accuracy, such as mm for building and other trade contexts, cm for textiles

#### 1.3.3

convert between metric units of length and other length units for simple practical purposes, for example, 1 inch ≈ 2.54cm

#### 1.3.4

calculate perimeters of familiar shapes, including: triangles, squares, rectangles and composites of these