Interactive practice questions
We want to prove the sine rule: $\frac{\sin A}{a}=\frac{\sin B}{b}$sinAa=sinBb
Consider the $\triangle ACD$△ACD, find an expression for $\sin A$sinA.
Consider $\triangle BDC$△BDC, find an expression for $\sin B$sinB.
Make $x$x the subject of the equation $\sin B=\frac{x}{a}$sinB=xa.
Substitute $x=a\sin B$x=asinB into $\sin A=\frac{x}{b}$sinA=xb and prove the Sine Rule.
True or false:
$\frac{\sin A}{a}$sinAa=$\frac{\sin B}{b}$sinBb=$\frac{\sin C}{c}$sinCc
True
False
Consider a triangle where all three sides are known, but no angles are known. Is there enough information to find all the angles in the triangle using only the sine rule?
Consider a triangle where two of the angles and the side included between them are known. Is there enough information to solve for the remaining sides and angle using just the sine rule?
Consider a triangle where two of the sides and an angle included between them are known. Is there enough information to solve for the remaining side and angles using just the sine rule?